Project on electrolysis of potassium iodide for class 12th

                                            File:Michael Faraday. Photograph by Henry Dixon & Son Ltd ...

Today we will see how to make project on 'project on fire alarm for class 12th' this project is only for class 12th student and this project is belongs to 'chemistry' in this project we will cover following steps


1)Basic Aim 

2)Apparatus Used 

3)Theory 

Electrolysis Mechanism of 
electrolysis Quantitative aspects of electrolysis Faradays laws of electrolysis 
Products of electrolysis

4.Reactions Involved

5.Observations

6.Precautions


7.Biblography


                               AIM


TO STUDY THE ELECTROLYSIS OF PRODUCTS OF POTASSIUM IODIDE (KI)


            Apparatus required


1 U-Tube stand ,
2 Electrodes ,
3 KI solution ,
4 battery eliminator.


                           THEORY:-


Electrolysis

It is defined as a process of decomposition of an electrolyte by the passage of electricity through its aqueous solution or molten (fused) state.


MECHANISM OF ELECTROLYSIS

Whenever an electrolyte is dissolved in water or is taken in the molten state, the electrolyte dissociates to produce Positively and Negatively charged ions. On passing electric current, the positively charged ions move towards the cathode and hence are called cations, whereas the negatively charged ions move towards the anode and hence are called anions. On reaching their respective electrodes, ions lose their charge and become neutral. The cations accept electrons from the cathode to become neutral species. Thus, oxidation occurs at the anode while reduction reduction takes place at the anode. The conversion of ions into neutral species at their respective electrodes is called Primary change. The product formed as a result of primary change may be collected as such or it may go under a Secondary change to form the final products.


QUANTITATIVE ASPECTS OF ELECTROLYSIS


Michael Faraday was the first scientist who described the quantitative aspects of electrolysis.

Faraday’s Laws Of Electrolysis-

First Law:- The amount of chemical reaction which occurs at any electrode during electrolysis by a current is proportional to the quantity of electricity passed through the electrolyte (solution or melt).

Second Law :- The amounts of different substances liberated by the same quantity of electricity passing through the electrolytic solution are proportional to their chemical equivalent weights (atomic mass of metal – number of electrons required to reduce the cation).


PRODUCTS OF ELECTROLYSIS

Products of electrolysis depend on the nature of material being and the type of electrodes being used .If the electrode is inert, it does not participate in the chemical reaction and acts only as source or sink for electrons. On the other hand, if the electrode is reactive, it participates in the electrode reaction.Thus, the products of electrolysis may be different for reactive and inert electrodes. The products of electrolysis depend on the different oxidizing and reducing species present in the electrolytic cell and their standard electrode potentials. Moreover, some of the electrochemical processes although feasible, are so slow kinetically that at lower voltages these do not seem to take place and extra potential (called overvoltage) has to be applied, which makes such processes more difficult to occur.


       REACTIONS INVOLVED



In the electrolysis of an aqueous solution of KI, I ions are 
oxidized at the anode preferentially to water molecules. 
Possible

reactions at anode are as follows:-

2 𝐼(aq)  →              𝐼2 (g) + 2 𝑒……(1)
2 𝐻2O (l)    →          4 𝐻+(aq) + 𝑂2 + 4𝑒….(2)

Reaction (1) occurs in preference to reaction (2) due to 

standard electrode potential value of the following reaction.

2 𝐼(aq)       →         𝐼2 (g) + 2 𝑒…………(3)
EO /volt = + 0.53V

4 𝐻+(aq) + 𝑂2 + 4 𝑒−     →       2 𝐻2O (l)……(4)
𝐸𝑜 /volt = + 1.53V

Possible cathode reactions are:

𝐾+(aq) + 𝑒-   →          K (s) …………..(5)
𝐸𝑜 /volt = – 2.92V

2 𝐻2O(l) + 2𝑒−  →         𝐻2 (g) + 2 𝑂𝐻(aq)…6) 𝐸𝑜 /volt = – 0.83V

𝐸𝑜 value of reduction reaction (5) is much smaller than that of reaction (6). Thus, reaction (6) occurs competitively over reaction (5) at cathode.

Thus, violet colour of anode is due to formation of iodine and

 its subsequent reaction with starch Pink colour at cathode is 

due to formation of Hydroxide ions which also render the 

solution alkaline. Hydroxide ions give pink colour with phenolphthalein.


                 OBSERVATIONS



TEST SOLUTIONS
OBSERVATIOS

INFERENCE
Aqueous solution of potassium iodide with five drops of phenolphthalein and five drops of starch solution.
At the anode, violet colour. At the cathode:

(i )Pink colour (ii)Formation of bubbles
Free iodine is evolved.
(i)OH– ion is formed
(ii)Hydrogen is evolved


PRECAUTIONS

1) Both the electrodes should be loosely fixed into the U- tube so as to allow the escape of evolved gasses.
2) Electrodes should be cleaned before use.


CONCLUSION

In the electrolysis of an aqueous solution of potassium iodide, I– ions are oxidized at the anode preferentially to water molecules. Violet colour at anode is due to iodine. Pink colour at cathode is due to formation of OH– ions which renders the solution alkaline. OH– ions give pink colour with phenolphthalein.

BIBLOGRAPHY


1) Experiments on formal level topics in Chemistry. 2) 2)Chemistry – a textbook for class XII. 3) Internet 3)wikipedia.com.




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